14-07-13, 09:46 PM
(14-07-13, 08:03 PM)pointer2null link Wrote: Yes in a way (strictly speaking the load is A x V (V X A = P when P is power in Watts))
Anyway, I thought load was the resistance applied across a circuit, V=IR, power is equivalent to the energy spent overcoming the resistance - but it's years since I did anything in electronics and I was never the most avid student!