04-11-12, 10:18 PM
yes i see what you mean I=V/R. but if the resistance has increased due to a dodgy wire or connection then there would have to be more current flowing through the circuit to maintain the 12V wouldn't there? and if heat is proportional to the current squared and there's a higher resistance then you've got more heat. i'm only guessing here btw you probably know more about it than me