07-04-12, 09:58 AM
The short answer is there may be some commas mixed up with decimal points and the speed is reasonable.
The long answer is:
r = c/(pi*2), c = pi*2*r, s = d/t, t = d/t
r = radius, c= circumference, s = speed, d = distance, t = time
c(earth) = 24901.55 miles @ equator, 24859.82 miles pole to pole ==> average 24880.69 miles
h(orbit) = 240 miles
s = 17239.2 miles per hour
c(orbit) needs calculating:
r(orbit) = r(earth) + h(orbit) ==> c(earth)/(pi*2) + h(orbit)
r(orbit) = 24880.69/(pi*2) 240 ==> 3959.88 240
r(orbit) = 4199.88
c(orbit) = r(orbit)*pi*2 ==> 4199.88*pi*2
c(orbit) = 26388.65 miles
t = d/s ==> t(orbit) = c(orbit)/s
t = 26388.65 / 17239.2 ==> 1.5307 hours
t = 1.5 hours
Due to the earth not being perfectly spherical, variations in the height of orbit and errors in the measured quantities this value can only be considered an approximation.
The long answer is:
r = c/(pi*2), c = pi*2*r, s = d/t, t = d/t
r = radius, c= circumference, s = speed, d = distance, t = time
c(earth) = 24901.55 miles @ equator, 24859.82 miles pole to pole ==> average 24880.69 miles
h(orbit) = 240 miles
s = 17239.2 miles per hour
c(orbit) needs calculating:
r(orbit) = r(earth) + h(orbit) ==> c(earth)/(pi*2) + h(orbit)
r(orbit) = 24880.69/(pi*2) 240 ==> 3959.88 240
r(orbit) = 4199.88
c(orbit) = r(orbit)*pi*2 ==> 4199.88*pi*2
c(orbit) = 26388.65 miles
t = d/s ==> t(orbit) = c(orbit)/s
t = 26388.65 / 17239.2 ==> 1.5307 hours
t = 1.5 hours
Due to the earth not being perfectly spherical, variations in the height of orbit and errors in the measured quantities this value can only be considered an approximation.
thou shalt not kick