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+--- Thread: Digital Camera (Cheap ones) (/showthread.php?tid=64440)
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Re: Digital Camera (Cheap ones) - BBROWN1664 - 14-07-13
The load = the A part
Re: Digital Camera (Cheap ones) - pointer2null - 14-07-13
Yes in a way (strictly speaking the load is A x V (V X A = P when P is power in Watts))
Re: Digital Camera (Cheap ones) - simonm - 14-07-13
(14-07-13, 07:51 PM)pointer2null link Wrote: You haven't seen my phone lol
mAh - does apply to all batteries; it's a measure of capacity. Although with a Duracell it varies with load
If a battery doesn't specify mah due to its chemistry then as far as I'm concerned it's incomparable. Therefore whilst you're correct, and I am incorrect, you cannot compare a rechargeable with an alkaline as each has its benefits and disadvantages.
Yes, I've decended in to talking rubbish but whilst I know what I mean I can't be bothered to explain any more.
Re: Digital Camera (Cheap ones) - simonm - 14-07-13
As an aside I'd always go for a camera with a proprietary li-ion battery over one that took aa's.
The aa form factor is not convenient compared to a rectangular pack.
Only one of my digi cameras takes aa's and its the cheapest one that I use underwater. My Panasonic dmc t27, my eos and my ixus all use proprietary li-ion batteries.
Re: Digital Camera (Cheap ones) - nick crisp - 14-07-13
Ye Gods, I'm only a happy snapper! Think I'll stick to what I know... :lol
Re: Digital Camera (Cheap ones) - nick crisp - 14-07-13
(14-07-13, 08:03 PM)pointer2null link Wrote: Yes in a way (strictly speaking the load is A x V (V X A = P when P is power in Watts))
Anyway, I thought load was the resistance applied across a circuit, V=IR, power is equivalent to the energy spent overcoming the resistance - but it's years since I did anything in electronics and I was never the most avid student!
Re: Digital Camera (Cheap ones) - simonm - 14-07-13
P=VI where p is the power in watts, V is the voltage and I is the current in amps